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<script>
    



    // 1. js 统计一个字符串出现频率最高的字母/数字

    // 数组去重
    let arr = [1,2,3,4,5,1,2,3,66,66]
    
    let newArr = arr.reduce((prve,next)=>{
        if(prve.indexOf(next) === -1 ){
            prve.push(next)
        }
        return prve
    },[])
    console.log(newArr);
    let obj = {}
    console.log(obj);
    class Super{
        constructor(){

        }
    }

    // 2. 数组中最大差值





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